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Military Mach 20 in 2011 WOW! UFO Will TRavel at Mach 880980

February 17, 2016

Hypersonic Technology Vehicle HTV-2 reentry (artist's impression)

Military unmanned vehicle travels at Mach 20 in 2011 WOW! UFO Will TRavel at Mach 880980

speed of light per second 299 792 458 m / s2

what is 20 times the speed of sound

6 805.8 m / s

the speed of light per second =
299 792 458 m / s2

299792458/6805.8 = 44049.5544976
so the UFO can travel at 44049.55 faster than Mach 20.

I’m not sure how to do these calculations. I’m sure some one else can figure it out! 🙂

Just thought I’d try to figure it out for fun.

44049.5544976 / 6 805.8 = 6.47235512322

 

quote

Despite the problem, the aircraft reached speeds around Mach 20 (about 13,000 mph) and was able to control its flight for several minutes, officials said.

“HTV-2 demonstrated stable, aerodynamically controlled Mach 20 hypersonic flight for approximately three minutes,” said DARPA director Regina Dugan in an Aug. 14 statement. “We do not yet know the cause of the anomaly for Flight 2.”

– See more at: http://www.space.com/12670-superfast-hypersonic-military-aircraft-darpa-htv2.html#sthash.Ilxn4PVl.dpuf

see military story here
http://www.space.com/12670-superfast-hypersonic-military-aircraft-darpa-htv2.html

 

my thoughts

first test problem

quote

engineers to adjust the HTV-2’s center of gravity

 

quote wiki

Center of gravity is the point in a body around which the resultant torque due to gravity forces vanishes. Where a gravity field can be considered to be uniform, the mass-center and the center-of-gravity will be the same. However, for satellites in orbit around a planet, in the absence of other torques being applied to a satellite, the slight variation (gradient) in gravitational field between closer-to (stronger) and further-from (weaker) the planet can lead to a torque that will tend to align the satellite such that its long axis is vertical. In such a case, it is important to make the distinction between the center-of-gravity and the mass-center. Any horizontal offset between the two will result in an applied torque.

https://en.wikipedia.org/wiki/Center_of_mass#Center_of_gravity

my thoughts

data mining! to figure out what your words all mean.

quote blog below

Torque ↔ Force Moment of Inertia ↔ Mass Angular Momentum ↔ Momentum

quote blog

you get a better angular acceleration by pushing further out

 

http://rockpile.phys.virginia.edu/arch15.pdf

 

Suvat_eom_any_direction_constant_acceleration.svg

Suvat_eom_any_direction_constant_acceleration.svg

 

quote wiki

Trajectory of a particle with initial position vector r0 and velocity v0, subject to constant acceleration a, all three quantities in any direction, and the position r(t) and velocity v(t) after time t.

 

Acceleration vector a, not parallel to the radial motion but offset by the angular and Coriolis accelerations, nor tangent to the path but offset by the centripetal and radial accelerations.

quote wiki

Acceleration vector a, not parallel to the radial motion but offset by the angular and Coriolis accelerations, nor tangent to the path but offset by the centripetal and radial accelerations.

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